Poodletooth-iLand/panda/python/Lib/site-packages/Crypto/Protocol/AllOrNothing.py

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2015-03-04 16:51:50 -06:00
#
# AllOrNothing.py : all-or-nothing package transformations
#
# Part of the Python Cryptography Toolkit
#
# Written by Andrew M. Kuchling and others
#
# ===================================================================
# The contents of this file are dedicated to the public domain. To
# the extent that dedication to the public domain is not available,
# everyone is granted a worldwide, perpetual, royalty-free,
# non-exclusive license to exercise all rights associated with the
# contents of this file for any purpose whatsoever.
# No rights are reserved.
#
# THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND,
# EXPRESS OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF
# MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND
# NONINFRINGEMENT. IN NO EVENT SHALL THE AUTHORS OR COPYRIGHT HOLDERS
# BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER IN AN
# ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN
# CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE
# SOFTWARE.
# ===================================================================
"""This file implements all-or-nothing package transformations.
An all-or-nothing package transformation is one in which some text is
transformed into message blocks, such that all blocks must be obtained before
the reverse transformation can be applied. Thus, if any blocks are corrupted
or lost, the original message cannot be reproduced.
An all-or-nothing package transformation is not encryption, although a block
cipher algorithm is used. The encryption key is randomly generated and is
extractable from the message blocks.
This class implements the All-Or-Nothing package transformation algorithm
described in:
Ronald L. Rivest. "All-Or-Nothing Encryption and The Package Transform"
http://theory.lcs.mit.edu/~rivest/fusion.pdf
"""
__revision__ = "$Id$"
import operator
import sys
from Crypto.Util.number import bytes_to_long, long_to_bytes
from Crypto.Util.py3compat import *
def isInt(x):
test = 0
try:
test += x
except TypeError:
return 0
return 1
class AllOrNothing:
"""Class implementing the All-or-Nothing package transform.
Methods for subclassing:
_inventkey(key_size):
Returns a randomly generated key. Subclasses can use this to
implement better random key generating algorithms. The default
algorithm is probably not very cryptographically secure.
"""
def __init__(self, ciphermodule, mode=None, IV=None):
"""AllOrNothing(ciphermodule, mode=None, IV=None)
ciphermodule is a module implementing the cipher algorithm to
use. It must provide the PEP272 interface.
Note that the encryption key is randomly generated
automatically when needed. Optional arguments mode and IV are
passed directly through to the ciphermodule.new() method; they
are the feedback mode and initialization vector to use. All
three arguments must be the same for the object used to create
the digest, and to undigest'ify the message blocks.
"""
self.__ciphermodule = ciphermodule
self.__mode = mode
self.__IV = IV
self.__key_size = ciphermodule.key_size
if not isInt(self.__key_size) or self.__key_size==0:
self.__key_size = 16
__K0digit = bchr(0x69)
def digest(self, text):
"""digest(text:string) : [string]
Perform the All-or-Nothing package transform on the given
string. Output is a list of message blocks describing the
transformed text, where each block is a string of bit length equal
to the ciphermodule's block_size.
"""
# generate a random session key and K0, the key used to encrypt the
# hash blocks. Rivest calls this a fixed, publically-known encryption
# key, but says nothing about the security implications of this key or
# how to choose it.
key = self._inventkey(self.__key_size)
K0 = self.__K0digit * self.__key_size
# we need two cipher objects here, one that is used to encrypt the
# message blocks and one that is used to encrypt the hashes. The
# former uses the randomly generated key, while the latter uses the
# well-known key.
mcipher = self.__newcipher(key)
hcipher = self.__newcipher(K0)
# Pad the text so that its length is a multiple of the cipher's
# block_size. Pad with trailing spaces, which will be eliminated in
# the undigest() step.
block_size = self.__ciphermodule.block_size
padbytes = block_size - (len(text) % block_size)
text = text + b(' ') * padbytes
# Run through the algorithm:
# s: number of message blocks (size of text / block_size)
# input sequence: m1, m2, ... ms
# random key K' (`key' in the code)
# Compute output sequence: m'1, m'2, ... m's' for s' = s + 1
# Let m'i = mi ^ E(K', i) for i = 1, 2, 3, ..., s
# Let m's' = K' ^ h1 ^ h2 ^ ... hs
# where hi = E(K0, m'i ^ i) for i = 1, 2, ... s
#
# The one complication I add is that the last message block is hard
# coded to the number of padbytes added, so that these can be stripped
# during the undigest() step
s = divmod(len(text), block_size)[0]
blocks = []
hashes = []
for i in range(1, s+1):
start = (i-1) * block_size
end = start + block_size
mi = text[start:end]
assert len(mi) == block_size
cipherblock = mcipher.encrypt(long_to_bytes(i, block_size))
mticki = bytes_to_long(mi) ^ bytes_to_long(cipherblock)
blocks.append(mticki)
# calculate the hash block for this block
hi = hcipher.encrypt(long_to_bytes(mticki ^ i, block_size))
hashes.append(bytes_to_long(hi))
# Add the padbytes length as a message block
i = i + 1
cipherblock = mcipher.encrypt(long_to_bytes(i, block_size))
mticki = padbytes ^ bytes_to_long(cipherblock)
blocks.append(mticki)
# calculate this block's hash
hi = hcipher.encrypt(long_to_bytes(mticki ^ i, block_size))
hashes.append(bytes_to_long(hi))
# Now calculate the last message block of the sequence 1..s'. This
# will contain the random session key XOR'd with all the hash blocks,
# so that for undigest(), once all the hash blocks are calculated, the
# session key can be trivially extracted. Calculating all the hash
# blocks requires that all the message blocks be received, thus the
# All-or-Nothing algorithm succeeds.
mtick_stick = bytes_to_long(key) ^ reduce(operator.xor, hashes)
blocks.append(mtick_stick)
# we convert the blocks to strings since in Python, byte sequences are
# always represented as strings. This is more consistent with the
# model that encryption and hash algorithms always operate on strings.
return [long_to_bytes(i,self.__ciphermodule.block_size) for i in blocks]
def undigest(self, blocks):
"""undigest(blocks : [string]) : string
Perform the reverse package transformation on a list of message
blocks. Note that the ciphermodule used for both transformations
must be the same. blocks is a list of strings of bit length
equal to the ciphermodule's block_size.
"""
# better have at least 2 blocks, for the padbytes package and the hash
# block accumulator
if len(blocks) < 2:
raise ValueError, "List must be at least length 2."
# blocks is a list of strings. We need to deal with them as long
# integers
blocks = map(bytes_to_long, blocks)
# Calculate the well-known key, to which the hash blocks are
# encrypted, and create the hash cipher.
K0 = self.__K0digit * self.__key_size
hcipher = self.__newcipher(K0)
block_size = self.__ciphermodule.block_size
# Since we have all the blocks (or this method would have been called
# prematurely), we can calculate all the hash blocks.
hashes = []
for i in range(1, len(blocks)):
mticki = blocks[i-1] ^ i
hi = hcipher.encrypt(long_to_bytes(mticki, block_size))
hashes.append(bytes_to_long(hi))
# now we can calculate K' (key). remember the last block contains
# m's' which we don't include here
key = blocks[-1] ^ reduce(operator.xor, hashes)
# and now we can create the cipher object
mcipher = self.__newcipher(long_to_bytes(key, self.__key_size))
# And we can now decode the original message blocks
parts = []
for i in range(1, len(blocks)):
cipherblock = mcipher.encrypt(long_to_bytes(i, block_size))
mi = blocks[i-1] ^ bytes_to_long(cipherblock)
parts.append(mi)
# The last message block contains the number of pad bytes appended to
# the original text string, such that its length was an even multiple
# of the cipher's block_size. This number should be small enough that
# the conversion from long integer to integer should never overflow
padbytes = int(parts[-1])
text = b('').join(map(long_to_bytes, parts[:-1]))
return text[:-padbytes]
def _inventkey(self, key_size):
# Return key_size random bytes
from Crypto import Random
return Random.new().read(key_size)
def __newcipher(self, key):
if self.__mode is None and self.__IV is None:
return self.__ciphermodule.new(key)
elif self.__IV is None:
return self.__ciphermodule.new(key, self.__mode)
else:
return self.__ciphermodule.new(key, self.__mode, self.__IV)
if __name__ == '__main__':
import sys
import getopt
import base64
usagemsg = '''\
Test module usage: %(program)s [-c cipher] [-l] [-h]
Where:
--cipher module
-c module
Cipher module to use. Default: %(ciphermodule)s
--aslong
-l
Print the encoded message blocks as long integers instead of base64
encoded strings
--help
-h
Print this help message
'''
ciphermodule = 'AES'
aslong = 0
def usage(code, msg=None):
if msg:
print msg
print usagemsg % {'program': sys.argv[0],
'ciphermodule': ciphermodule}
sys.exit(code)
try:
opts, args = getopt.getopt(sys.argv[1:],
'c:l', ['cipher=', 'aslong'])
except getopt.error, msg:
usage(1, msg)
if args:
usage(1, 'Too many arguments')
for opt, arg in opts:
if opt in ('-h', '--help'):
usage(0)
elif opt in ('-c', '--cipher'):
ciphermodule = arg
elif opt in ('-l', '--aslong'):
aslong = 1
# ugly hack to force __import__ to give us the end-path module
module = __import__('Crypto.Cipher.'+ciphermodule, None, None, ['new'])
x = AllOrNothing(module)
print 'Original text:\n=========='
print __doc__
print '=========='
msgblocks = x.digest(b(__doc__))
print 'message blocks:'
for i, blk in zip(range(len(msgblocks)), msgblocks):
# base64 adds a trailing newline
print ' %3d' % i,
if aslong:
print bytes_to_long(blk)
else:
print base64.encodestring(blk)[:-1]
#
# get a new undigest-only object so there's no leakage
y = AllOrNothing(module)
text = y.undigest(msgblocks)
if text == b(__doc__):
print 'They match!'
else:
print 'They differ!'