156 lines
4.1 KiB
C
156 lines
4.1 KiB
C
/*
|
|
* (C) Copyright 2001
|
|
* Wolfgang Denk, DENX Software Engineering, wd@denx.de.
|
|
*
|
|
* See file CREDITS for list of people who contributed to this
|
|
* project.
|
|
*
|
|
* This program is free software; you can redistribute it and/or
|
|
* modify it under the terms of the GNU General Public License as
|
|
* published by the Free Software Foundation; either version 2 of
|
|
* the License, or (at your option) any later version.
|
|
*
|
|
* This program is distributed in the hope that it will be useful,
|
|
* but WITHOUT ANY WARRANTY; without even the implied warranty of
|
|
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
|
|
* GNU General Public License for more details.
|
|
*
|
|
* You should have received a copy of the GNU General Public License
|
|
* along with this program; if not, write to the Free Software
|
|
* Foundation, Inc., 59 Temple Place, Suite 330, Boston,
|
|
* MA 02111-1307 USA
|
|
*/
|
|
|
|
/*
|
|
* Date & Time support for Philips PCF8563 RTC
|
|
*/
|
|
|
|
#include <common.h>
|
|
#include <command.h>
|
|
#include <rtc.h>
|
|
|
|
#if defined(CONFIG_CMD_DATE) || defined(CONFIG_TIMESTAMP)
|
|
|
|
#define FEBRUARY 2
|
|
#define STARTOFTIME 1970
|
|
#define SECDAY 86400L
|
|
#define SECYR (SECDAY * 365)
|
|
#define leapyear(year) ((year) % 4 == 0)
|
|
#define days_in_year(a) (leapyear(a) ? 366 : 365)
|
|
#define days_in_month(a) (month_days[(a) - 1])
|
|
|
|
static int month_days[12] = {
|
|
31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31
|
|
};
|
|
|
|
/*
|
|
* This only works for the Gregorian calendar - i.e. after 1752 (in the UK)
|
|
*/
|
|
void GregorianDay(struct rtc_time * tm)
|
|
{
|
|
int leapsToDate;
|
|
int lastYear;
|
|
int day;
|
|
int MonthOffset[] = { 0,31,59,90,120,151,181,212,243,273,304,334 };
|
|
|
|
lastYear=tm->tm_year-1;
|
|
|
|
/*
|
|
* Number of leap corrections to apply up to end of last year
|
|
*/
|
|
leapsToDate = lastYear/4 - lastYear/100 + lastYear/400;
|
|
|
|
/*
|
|
* This year is a leap year if it is divisible by 4 except when it is
|
|
* divisible by 100 unless it is divisible by 400
|
|
*
|
|
* e.g. 1904 was a leap year, 1900 was not, 1996 is, and 2000 will be
|
|
*/
|
|
if((tm->tm_year%4==0) &&
|
|
((tm->tm_year%100!=0) || (tm->tm_year%400==0)) &&
|
|
(tm->tm_mon>2)) {
|
|
/*
|
|
* We are past Feb. 29 in a leap year
|
|
*/
|
|
day=1;
|
|
} else {
|
|
day=0;
|
|
}
|
|
|
|
day += lastYear*365 + leapsToDate + MonthOffset[tm->tm_mon-1] + tm->tm_mday;
|
|
|
|
tm->tm_wday=day%7;
|
|
}
|
|
|
|
void to_tm(int tim, struct rtc_time * tm)
|
|
{
|
|
register int i;
|
|
register long hms, day;
|
|
|
|
day = tim / SECDAY;
|
|
hms = tim % SECDAY;
|
|
|
|
/* Hours, minutes, seconds are easy */
|
|
tm->tm_hour = hms / 3600;
|
|
tm->tm_min = (hms % 3600) / 60;
|
|
tm->tm_sec = (hms % 3600) % 60;
|
|
|
|
/* Number of years in days */
|
|
for (i = STARTOFTIME; day >= days_in_year(i); i++) {
|
|
day -= days_in_year(i);
|
|
}
|
|
tm->tm_year = i;
|
|
|
|
/* Number of months in days left */
|
|
if (leapyear(tm->tm_year)) {
|
|
days_in_month(FEBRUARY) = 29;
|
|
}
|
|
for (i = 1; day >= days_in_month(i); i++) {
|
|
day -= days_in_month(i);
|
|
}
|
|
days_in_month(FEBRUARY) = 28;
|
|
tm->tm_mon = i;
|
|
|
|
/* Days are what is left over (+1) from all that. */
|
|
tm->tm_mday = day + 1;
|
|
|
|
/*
|
|
* Determine the day of week
|
|
*/
|
|
GregorianDay(tm);
|
|
}
|
|
|
|
/* Converts Gregorian date to seconds since 1970-01-01 00:00:00.
|
|
* Assumes input in normal date format, i.e. 1980-12-31 23:59:59
|
|
* => year=1980, mon=12, day=31, hour=23, min=59, sec=59.
|
|
*
|
|
* [For the Julian calendar (which was used in Russia before 1917,
|
|
* Britain & colonies before 1752, anywhere else before 1582,
|
|
* and is still in use by some communities) leave out the
|
|
* -year/100+year/400 terms, and add 10.]
|
|
*
|
|
* This algorithm was first published by Gauss (I think).
|
|
*
|
|
* WARNING: this function will overflow on 2106-02-07 06:28:16 on
|
|
* machines were long is 32-bit! (However, as time_t is signed, we
|
|
* will already get problems at other places on 2038-01-19 03:14:08)
|
|
*/
|
|
unsigned long
|
|
mktime (unsigned int year, unsigned int mon,
|
|
unsigned int day, unsigned int hour,
|
|
unsigned int min, unsigned int sec)
|
|
{
|
|
if (0 >= (int) (mon -= 2)) { /* 1..12 -> 11,12,1..10 */
|
|
mon += 12; /* Puts Feb last since it has leap day */
|
|
year -= 1;
|
|
}
|
|
|
|
return (((
|
|
(unsigned long) (year/4 - year/100 + year/400 + 367*mon/12 + day) +
|
|
year*365 - 719499
|
|
)*24 + hour /* now have hours */
|
|
)*60 + min /* now have minutes */
|
|
)*60 + sec; /* finally seconds */
|
|
}
|
|
|
|
#endif
|