280 lines
No EOL
13 KiB
Python
280 lines
No EOL
13 KiB
Python
#################################################################
|
|
# File: HolidayInfoRelatively.py
|
|
# Purpose: To have a means of specifying a holiday as
|
|
# the position of a specific weekday in a month.
|
|
# For instance Halloween is the 5th Friday of October.
|
|
#################################################################
|
|
|
|
#################################################################
|
|
# Toontown Specific Modules
|
|
#################################################################
|
|
from toontown.ai.HolidayInfo import *
|
|
|
|
#################################################################
|
|
# Python Specific Modules
|
|
#################################################################
|
|
import calendar
|
|
import random
|
|
import time
|
|
from copy import deepcopy
|
|
import functools
|
|
from enum import IntEnum
|
|
|
|
|
|
Day = IntEnum("Day", ('MONDAY', 'TUESDAY', 'WEDNESDAY', 'THURSDAY', \
|
|
'FRIDAY', 'SATURDAY', 'SUNDAY'), start=0)
|
|
|
|
#################################################################
|
|
# Class: HolidayInfo_Relatively
|
|
# Purpose: Stores all relevant information regarding an event,
|
|
# such as the type of event.
|
|
#################################################################
|
|
class HolidayInfo_Relatively(HolidayInfo_Base):
|
|
#############################################################
|
|
# Method: __init__
|
|
# Purpose: Provides initial construction of the Monthly Holiday
|
|
# Info object. It generates the list of times that
|
|
# the holiday should be run every week.
|
|
# Input: holidayClass - class type of the holiday, for
|
|
# instance - Halloween.
|
|
# dateList - The date is specified as a pair of the
|
|
# following:
|
|
# [(Month.OCTOBER, 5, Day.FRIDAY, 10, 0, 0),
|
|
# (Month.OCTOBER, 5, Day.FRIDAY, 15, 0, 0) ]
|
|
# This means that the holiday is on the 5th Friday of October
|
|
# between 10am and 3pm.
|
|
# Output: None
|
|
############################################################
|
|
def __init__(self, holidayClass, dateList, displayOnCalendar):
|
|
HolidayInfo_Base.__init__(self, holidayClass, displayOnCalendar)
|
|
|
|
dateElemIter = ModifiedIter(dateList)
|
|
for i in range(len(dateList)//2):
|
|
start = dateElemIter.current()
|
|
end = next(dateElemIter)
|
|
|
|
self.tupleList.append((start, end))
|
|
next(dateElemIter)
|
|
|
|
self.tupleList.sort(key=functools.cmp_to_key(cmpDates))
|
|
self.weekDaysInMonth = [] # A matrix of the number of times a weekday repeats in a month
|
|
self.numDaysCorMatrix = [(28,0), (29, 1),
|
|
(30, 2), (31, 3)] # A matrix of the number of weekdays that repeat one extra
|
|
# time based on the number of days in the month. For instance
|
|
# in a month with 31 days, the first two week days occur
|
|
# one more time than the other days.
|
|
for i in range(7): # The minimum number of times a day repeats in a month
|
|
self.weekDaysInMonth.append((i,4))
|
|
|
|
############################################################
|
|
# Method: initRepMatrix
|
|
# Initialize the number of times weekdays get
|
|
# repeated in a month method.
|
|
############################################################
|
|
def initRepMatrix(self, year, month):
|
|
|
|
for i in range(7):
|
|
self.weekDaysInMonth[i] = (i,4)
|
|
|
|
startingWeekDay, numDays = calendar.monthrange(year, month)
|
|
|
|
for i in range(4):
|
|
if(numDays == self.numDaysCorMatrix[i][0]):
|
|
break
|
|
|
|
for j in range(self.numDaysCorMatrix[i][1]): # At this point we have a matrix of the weekdays and
|
|
self.weekDaysInMonth[startingWeekDay] = (self.weekDaysInMonth[startingWeekDay][0],
|
|
self.weekDaysInMonth[startingWeekDay][1]+1) # the number of times they repeat for the current month
|
|
startingWeekDay = (startingWeekDay+1)%7
|
|
|
|
#############################################################
|
|
# Method: getTime
|
|
# Purpose: This method returns the time. Overrides the base
|
|
# definiton of HolidayInfo.
|
|
# Input: date - the current date represented as a tuple
|
|
# Output: returns the time in secs based on date and t
|
|
#############################################################
|
|
def getTime(self, date, t):
|
|
# t is of the form (day, hour, min, sec)
|
|
# date is of the form (year, month, day, weekday)
|
|
repNum = t[1]
|
|
weekday = t[2]
|
|
self.initRepMatrix(date[0],t[0])
|
|
while(self.weekDaysInMonth[weekday][1] < repNum):
|
|
repNum -= 1
|
|
|
|
day = self.dayForWeekday(date[0], t[0], weekday, repNum)
|
|
|
|
return time.mktime((date[0], # year
|
|
t[0], # month
|
|
day, # day
|
|
t[3], # hour
|
|
t[4], # second
|
|
t[5], # minute
|
|
0,
|
|
0,
|
|
-1))
|
|
|
|
#############################################################
|
|
# Method: getStartTime
|
|
# Purpose: This method returns the current start time of
|
|
# the holiday.
|
|
# Input: date - the current date represented as a tuple
|
|
# Output: returns current start time
|
|
#############################################################
|
|
def getStartTime(self, date):
|
|
startTuple, endTuple = self.getUpdatedTuples(self.currElemIter.current())
|
|
return self.getTime(date, startTuple)
|
|
|
|
#############################################################
|
|
# Method: getEndTime
|
|
# Purpose: This method returns the current end time of
|
|
# the holiday.
|
|
# Input: date - the current date represented as a tuple
|
|
# Output: returns current end time
|
|
#############################################################
|
|
def getEndTime(self, date):
|
|
startTuple, endTuple = self.getUpdatedTuples(self.currElemIter.current())
|
|
return self.getTime(date, endTuple)
|
|
|
|
#############################################################
|
|
# Method: getNextHolidayTime
|
|
# Purpose: This method finds the next appropriate time to
|
|
# start this holiday. It searches through the list
|
|
# of time tuples, and performs the necessary
|
|
# computations for finding the time.
|
|
# Input: currTime - current time
|
|
# Output: returns the next start time of the holiday
|
|
#############################################################
|
|
def getNextHolidayTime(self, currTime):
|
|
sCurrYear = time.localtime()[0]
|
|
eCurrYear = sCurrYear
|
|
|
|
for i in range(len(self.tupleList)):
|
|
startTuple, endTuple = self.getUpdatedTuples(self.currElemIter.peekNext())
|
|
sMonth = startTuple[0]
|
|
nMonth = endTuple[0]
|
|
# If the end month is less than the start month, it is
|
|
# in the proceeding year. Adjust the end year accordingly.
|
|
# This assures that the proper time tuple will be chosen from
|
|
# the list.
|
|
if endTuple[0] < startTuple[0]:
|
|
eCurrYear += 1
|
|
|
|
if sMonth > nMonth:
|
|
# The holiday should be scheduled in the
|
|
# following year. There are two cases that
|
|
# may exist and they follow:
|
|
# Case 1: { May: [31], July: [(31)] }
|
|
# - Here, we end on July 31. The next
|
|
# time the holiday should start is on
|
|
# May 31, which would be in the following
|
|
# year.
|
|
# Case 2: { December: [(31, 1)], May: [31] }
|
|
# - Here, we end on January 1 of the new year,
|
|
# because this holiday spans from December
|
|
# to January. The next time the holiday should
|
|
# start is on May 31, which would be in the
|
|
# same year.
|
|
|
|
# Check to see if we are already in the next
|
|
# year due to overlapping holiday.
|
|
cMonth = time.localtime()[1]
|
|
if cMonth > nMonth:
|
|
# We have not crossed over into the new week
|
|
# as found in case 1.
|
|
sTime = self.getTime((sCurrYear+1,), startTuple)
|
|
eTime = self.getTime((eCurrYear+1,), endTuple)
|
|
else:
|
|
# We have already started the new year as found
|
|
# in case 2. Adjust time normally.
|
|
sTime = self.getTime((sCurrYear,), startTuple)
|
|
eTime = self.getTime((eCurrYear,), endTuple)
|
|
elif sMonth == nMonth:
|
|
if sDay > nDay:
|
|
# Since the next day is less than the current day,
|
|
# then we have reached the end of the list and the next
|
|
# date should be in the proceeding year.
|
|
sTime = self.getTime((sCurrYear+1,), startTuple)
|
|
eTime = self.getTime((eCurrYear+1,), endTuple)
|
|
elif sDay == nDay:
|
|
# Since the next tuple is of the same day, we must check
|
|
# the time tuples to see if the next time is greater than
|
|
# the current. If it is, that means we have reached the end
|
|
# of the list and should go into the next year..
|
|
curr = self.currElemIter.current()[0]
|
|
|
|
time1 = (curr[3], curr[4], curr[5])
|
|
time2 = (startTuple[3], startTuple[4], startTuple[5])
|
|
|
|
if time1 > time2:
|
|
sTime = self.getTime((sCurrYear+1,), startTuple)
|
|
eTime = self.getTime((eCurrYear+1,), endTuple)
|
|
else:
|
|
sTime = self.getTime((sCurrYear,), startTuple)
|
|
eTime = self.getTime((eCurrYear,), endTuple)
|
|
else:
|
|
# We have not reached the end of the list, calculate times
|
|
# accordingly.
|
|
sTime = self.getTime((sCurrYear,), startTuple)
|
|
eTime = self.getTime((eCurrYear,), endTuple)
|
|
else:
|
|
# We have not reached the end of the list, calculate times
|
|
# accordingly.
|
|
sTime = self.getTime((sCurrYear,), startTuple)
|
|
eTime = self.getTime((eCurrYear,), endTuple)
|
|
|
|
next(self.currElemIter)
|
|
if (currTime < eTime):
|
|
return sTime
|
|
|
|
# We are back to the original element, thus we should
|
|
# schedule it for the next year.
|
|
start = self.currElemIter.current()[0]
|
|
return self.getTime((sCurrYear+1,), start)
|
|
|
|
############################################################
|
|
# Method: getUpdatedTuples
|
|
# Returns the corrected pair of tuples based on
|
|
# the current month and year information
|
|
############################################################
|
|
def getUpdatedTuples(self, tuples):
|
|
sTuple = list(deepcopy(tuples[0]))
|
|
eTuple = list(deepcopy(tuples[1]))
|
|
sRepNum = sTuple[1]
|
|
sWeekday = sTuple[2]
|
|
eWeekday = eTuple[2]
|
|
while(1):
|
|
eRepNum = eTuple[1]
|
|
self.initRepMatrix(time.localtime()[0], sTuple[0])
|
|
while(self.weekDaysInMonth[sWeekday][1] < sRepNum):
|
|
sRepNum -= 1
|
|
sDay = self.dayForWeekday(time.localtime()[0], sTuple[0], sWeekday, sRepNum)
|
|
|
|
self.initRepMatrix(time.localtime()[0], eTuple[0])
|
|
while(self.weekDaysInMonth[eWeekday][1] < eRepNum):
|
|
eRepNum -= 1
|
|
nDay = self.dayForWeekday(time.localtime()[0], eTuple[0], eWeekday, eRepNum)
|
|
if(((nDay>sDay) and (eTuple[0] == sTuple[0]) \
|
|
and ((eTuple[1] - sTuple[1]) <= (nDay-sDay+abs(eWeekday-sWeekday))/7)) \
|
|
or (eTuple[0] != sTuple[0])):
|
|
break
|
|
|
|
# Handles the case when the end weekday is less than the start
|
|
if(self.weekDaysInMonth[eWeekday][1] > eRepNum):
|
|
eRepNum += 1
|
|
else:
|
|
eTuple[0] += 1
|
|
eTuple[1] = 1
|
|
return sTuple, eTuple
|
|
|
|
############################################################
|
|
# Method: dayForWeekday(month, weekday, repNum)
|
|
# Returns the day for a given weekday that has repeated
|
|
# repNum times for that month
|
|
############################################################
|
|
def dayForWeekday(self, year, month, weekday, repNum):
|
|
monthDays = calendar.monthcalendar(year, month)
|
|
if(monthDays[0][weekday] == 0):
|
|
repNum += 1
|
|
return monthDays[(repNum-1)][weekday] |