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common_funcs: Add enum flag bitwise shift operator overloads

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This adds bitwise shift operator overloads (<<, >>, <<=, >>=) in the macro DECLARE_ENUM_FLAG_OPERATORS(type)
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Morph 2021-09-13 16:01:20 -04:00
parent d180fd7c36
commit 3512cae623
1 changed files with 16 additions and 0 deletions
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16
src/common/common_funcs.h
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@ -61,6 +61,14 @@ __declspec(dllimport) void __stdcall DebugBreak(void);
using T = std::underlying_type_t<type>; \ using T = std::underlying_type_t<type>; \
return static_cast<type>(static_cast<T>(a) ^ static_cast<T>(b)); \ return static_cast<type>(static_cast<T>(a) ^ static_cast<T>(b)); \
} \ } \
[[nodiscard]] constexpr type operator<<(type a, type b) noexcept { \
using T = std::underlying_type_t<type>; \
return static_cast<type>(static_cast<T>(a) << static_cast<T>(b)); \
} \
[[nodiscard]] constexpr type operator>>(type a, type b) noexcept { \
using T = std::underlying_type_t<type>; \
return static_cast<type>(static_cast<T>(a) >> static_cast<T>(b)); \
} \
constexpr type& operator|=(type& a, type b) noexcept { \ constexpr type& operator|=(type& a, type b) noexcept { \
a = a | b; \ a = a | b; \
return a; \ return a; \
@ -73,6 +81,14 @@ __declspec(dllimport) void __stdcall DebugBreak(void);
a = a ^ b; \ a = a ^ b; \
return a; \ return a; \
} \ } \
constexpr type& operator<<=(type& a, type b) noexcept { \
a = a << b; \
return a; \
} \
constexpr type& operator>>=(type& a, type b) noexcept { \
a = a >> b; \
return a; \
} \
[[nodiscard]] constexpr type operator~(type key) noexcept { \ [[nodiscard]] constexpr type operator~(type key) noexcept { \
using T = std::underlying_type_t<type>; \ using T = std::underlying_type_t<type>; \
return static_cast<type>(~static_cast<T>(key)); \ return static_cast<type>(~static_cast<T>(key)); \